Tom Morris

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graph.add_triple x.tom, foaf.knows, x.dan?

I'm afraid the jena equivalent would be:

model.add(X.tom, FOAF.knows, X.dan)

I love ruby, but this doesn't show its advantages (your jena example does more work).
Damian | 2008-03-04EST00:04:55+00:00 #

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